oracle基本建表語句

--創建用戶

create user han identified by han default tablespace

users Temporary TABLESPACE Temp;

grant connect,resource,dba to han; //授予用戶han開發人員的權利

--------------------對錶的操作--------------------------

--創建表

create table classes(

id number(9) not null primary key,

classname varchar2(40) not null

)

--查詢表

select * from classes;

--刪除表

drop table students;

--修改表的名稱

rename alist_table_copy to alist_table;

--顯示錶結構

describe test --不對沒查到

-----------------------對字段的操作-----------------------------------

--增加列

alter table test add address varchar2(40);

--刪除列

alter table test drop column address;

--修改列的名稱

alter table test modify address addresses varchar(40;

--修改列的屬性

alter table test modi

create table test1(

id number(9) primary key not null,

name varchar2(34)

)

rename test2 to test;

--創建自增的序列

create sequence class_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;

select class_seq.currval from dual

--插入數據

insert into classes values(class_seq.nextval,'軟件一班')

commit;

--更新數據

update stu_account set username='aaa' where count_id=2;

commit;

--創建唯一索引

create unique index username on stu_account(username); --唯一索引不能插入相同的數據

--行鎖 在新打開的對話中不能對此行進行操作

select * from stu_account t where t.count_id=2 for update; --行鎖

--alter table stuinfo modify sty_id to stu_id;

alter table students drop constraint class_fk;

alter table students add constraint class_fk foreign key (class_id) references classes(id);--外鍵約束

alter table stuinfo add constraint stu_fk foreign key (stu_id) references students(id) ON DELETE CASCADE;--外鍵約束,級聯刪除

alter table stuinfo drop constant stu_fk;

insert into students values(stu_seq.nextval,'張三',1,sysdate);

insert into stuinfo values(stu_seq.currval,'威海');

select * from stuinfo;

create table zhuce(

zc_id number(9) not null primary key,

stu_id number(9) not null,

zhucetime date default sysdate

)

create table feiyong (

fy_id number(9) not null primary key,

stu_id number(9) not null,

mx_id number(9) not null,

yijiao number(7,2) not null default 0,

qianfei number(7,2) not null

)

create talbe fymingxi(

mx_id number(9) not null primary key,

feiyong number(7,2) not null, //共7位數字,小數後有兩位

class_id number(9) not null

}

create table card(

card_id number(9) primary key,

stu_id number(9) not null,

money number(7,2) not null default 0,

status number(1) not null default 0 --0表可用,1表掛失

)

--鏈表查詢

select c.classname||'_'||s.stu_name as 班級_姓名,si.address from classes c,students s , stuinfo si where c.id=s.class_id and s.id=si.stu_id;

insert into students values(stu_seq.nextval,'李四',1,sysdate);

insert into stuinfo values(stu_seq.currval,'南京');

--函數

select rownum,id,stu_name from students t order by id asc;

--中間表實現多對多關聯

--(1 1, 1 n,n 1,n n )

--1 n的描述 1的表不作處理 n的表有1表的字段

--1 1的描述 主外鍵關聯

--n n的描述 中間表實現多對多關聯

create table course(

course_id number(9) not null,

couser_name varchar2(40) not null

)

alter table course to couse;

create table stu_couse(

stu_couse_id number(9) primary key,

stu_id number(9) not null,

couse_id number(9) not null

)

create unique index stu_couse_unq on stu_couse(stu_id,couse_id); --唯一學生

create sequence stu_couse_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;

create sequence couses_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;

insert into course values(couses_seq.nextval,'計算機原理');

insert into course values(couses_seq.nextval,'編譯原理');

insert into course values(couses_seq.nextval,'數據庫原理');

insert into course values(couses_seq.nextval,'數據結構');

insert into course values(couses_seq.nextval,'計算機基礎');

insert into course values(couses_seq.nextval,'C語言初步');

commit;

insert into stu_couse values(stu_couse_seq.nextval,1,1);

insert into stu_couse values(stu_couse_seq.nextval,1,3);

insert into stu_couse values(stu_couse_seq.nextval,1,5);

insert into stu_couse values(stu_couse_seq.nextval,1,5);

insert into stu_couse values(stu_couse_seq.nextval,2,1);

commit;

select * from stu_couse;

select * from course;

--select s.stu_name,sc.couse_id, c.couser_name from students s,course c,stu_couse sc where stu_id=1

--select couse_id from stu_couse where stu_id=1

select cl.classname,s.stu_name,c.couser_name from stu_couse sc, students s,course c,classes cl where s.id=sc.stu_id and sc.couse_id=c.course_id and s.class_id=cl.id and s.id=1;

--班級——姓名

select c.classname,s.stu_name from students s,classes c where s.class_id=c.id and s.id=2;

select * from students s where s.id=2

--班級——姓名——課程

select cl.classname,s.stu_name,c.couse_name from stu_couse sc,students s,classes cl,couse c where sc.stu_id=s.id and sc.couse_id=c.couse_id and s.id=26;

--sql 語句的寫法,現寫出關聯到的表,然後寫出要查找的字段,第三 寫出關聯條件 ,記住在寫關聯到的表時先寫數據多的表,這樣有助於提高sql的效率

select c.couser_name,s.stu_name from stu_couse sc,students s,course c where c.course_id=1 and c.course_id=sc.couse_id and sc.stu_id=s.id;

select s.stu_name from students s,stu_couse sc where s.id=sc.stu_id group by s.id,s.stu_name;

select c.classname,count(sc.couse_id) from stu_couse sc,students s,classes c where s.class_id=c.id and s.id=sc.stu_id group by c.classname;

select s.stu_name, count(sc.couse_id) from stu_couse sc,students s,classes cl where s.id=sc.stu_id group by s.id,s.stu_name having count(sc.stu_couse_id)>3;

班級 學生 選課數量

select cl.classname,count(sc.stu_couse_id) from stu_couse sc,students s,classes cl where s.id=sc.stu_id and s.class_id=cl.id group by cl.classname;

--班級 學生 選課數量

select cl.classname,s.stu_name,count(sc.stu_couse_id) from stu_couse sc,students s,classes cl where s.id=sc.stu_id and s.class_id=cl.id group by s.stu_name;

select cl.classname,s.stu_name,count(sc.stu_couse_id) from stu_couse sc ,students s,classes cl where sc.stu_id=s.id and s.class_id=cl.id group by s.id;

select cl.classname,s.stu_name,count(sc.stu_couse_id) from stu_couse sc,students s,classes cl where sc.stu_id=s.id and s.class_id=cl.id group by s.stu_name;

--班級 學生 所選課程id 所選課程名稱

--創建試圖 目的把表聯合起來 然後看成一個表,在與其他的聯合進行查詢

create view xsxk as select cl.classname, s.stu_name,c.couse_id, c.couse_name from stu_couse sc,students s,classes cl,couse c where sc.stu_id=s.id and sc.couse_id=c.couse_id and s.class_id=cl.id;

select * from xsxk

create view classstu as select s.id,c.classname,s.stu_name from students s,classes c where c.id=s.class_id;

drop view classstu; --刪除視圖

select * from classstu;

create view stu_couse_view as select s.id ,c.couse_name from stu_couse sc,students s,couse c where s.id=sc.stu_id and sc.couse_id=c.couse_id;

select * from stu_couse_view;

create view csc as select cs.classname,cs.stu_name,scv.couse_name from classstu cs,stu_couse_view scv where cs.id=scv.id;

select * from csc;

select * from classes cross join students; --全連接,相當於select * from classes,students;

select * from classes cl left join students s on cl.id=s.class_id; --左連接 不管左表有沒有 都顯示出來

select * from classes cl right join students s on cl.id=s.class_id; --右連接

select * from classes cl full join students s on cl.id=s.class_id; --全連接

insert into classes values(class_seq.nextval,'軟件四班');

create table sales(

nian varchar2(4),

yeji number(5)

);

insert into sales values('2001',200);

insert into sales values('2002',300);

insert into sales values('2003',400);

insert into sales values('2004',500);

commit;

select * from sales;

drop table sale;

select s1.nian,sum(s2.yeji) from sales s1,sales s2 where s1.nian>=s2.nian group by s1.nian order by s1.nian desc;

select s1.nian,sum(s2.yeji) from sales s1,sales s2 where s1.nian>=s2.nian group by s1.nian;

s

年 年業績總和

2001 200

2002 500

2003 900

2004 1400

create table test1(

t_id number(4)

);

create table org(

org_id number(9) not null primary key,

org_name varchar2(40) not null,

parent_id number(9)

);

create sequence org_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;

drop sequence org_seq;

insert into org values(1,'華建集團',0);

insert into org values(2,'華建集團一分公司',1);

insert into org values(3,'華建集團二分公司',1);

insert into org values(4,'華建集團財務部',1);

insert into org values(5,'華建集團工程部',1);

insert into org values(6,'華建集團一分公司財務處',2);

insert into org values(7,'華建集團一分公司工程處',2);

select * from org;

--不正確 不能實現循環

select b.org_id , b.org_name ,b.parent_id from org a,org b where a.org_id=7 and a.parent_id=b.org_id;

select * from org connect by prior parent_id=org_id start with org_id=7 order by org_id;

select * from org connect by prior org_id=parent_id start with org_id=1 order by org_id;

create table chengji(

cj_id number(9) not null primary key,

stu_cou_id number(9) not null,

fen number(4,1)

);

insert into chengji values(1,1,62);

insert into chengji values(2,2,90);

insert into chengji values(3,3,85);

insert into chengji values(4,4,45);

insert into chengji values(5,5,68);

insert into chengji values(6,6,87);

commit;

select * from chengji;

select * from stu_couse;

--在oracle 中好像不適用 alter table chengji change stu_cou_id stu_couse_id;alter table shop_jb change price1 price double;

學生姓名 平均分

select s.stu_name,avg(cj.fen) from stu_couse sc,chengji cj,students s where s.id=sc.stu_id and sc.stu_couse_id=cj.stu_couse_id group by s.id,s.stu_name;

select s.stu_name from students s,stu_couse sc,chengji cj where s.id=sc.stu_id and sc.stu_couse_id=cj.stu_couse_id group by s.id,s.stu_name;

select s.stu_name,cj.fen from students s,stu_couse sc,chengji cj where s.id=sc.stu_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen>60;

學生姓名 科目 成績

select s.stu_name,c.couse_name,cj.fen from stu_couse sc,students s,couse c,chengji cj where sc.stu_id=s.id and sc.couse_id=c.couse_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen>60 order by=;

select * from stu_couse;

--集合運算

--選擇了課程3的學生 union 選擇了課程5的學生 並集

--選擇了課程3 或者 選擇了課程5的學生

select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=3

union

select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=5

--選擇了課程3,5,2 的學生 intersect 選擇課程1,2,4的學生 交集

--求選擇了課程 2 並且 選擇了課程 3 的學生 交集

select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=2

intersect

select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=3;

--選擇了課程3,5,8的學生 minus 選擇了課程1,7,8的學生 --差集

-- 求所有課程的成績都大於 60 的學生 差集

select distinct(s.stu_name) from stu_couse sc,students s,couse c,chengji cj where sc.stu_id=s.id and sc.couse_id=c.couse_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen>60

minus

select distinct(s.stu_name) from stu_couse sc,students s,couse c,chengji cj where sc.stu_id=s.id and sc.couse_id=c.couse_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen<60;


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