一篇讀懂GRE數學中的代數與幾何問題

本篇帶大家詳細瞭解一下GRE數學中的代數與幾何問題。

知識點解讀,例題較多,耐心讀完思考思考,會有很新收穫哦!


01


代數


1、指數運算法則 Rules of Exponents

首先我們要熟練代數的運算法則:

一篇讀懂GRE數學中的代數與幾何問題


例題一:

Which of the following are equal to (1/560)-4 ?Indicate all correct answers.


一篇讀懂GRE數學中的代數與幾何問題


通過指數的運算規則可知:

(1/560)^-4=560^4

A:560^4*(560-1)/559=560^4

B:560^-10

C:70^4*8^4=560^4

D:560^8


所以答案為AD


2、函數 Function

y=f(x)稱為一個函數

Domain定義域為函數有定義的所有x值

Range值域為函數所有可能的取值


例題二:

★b=b+2 and ub=(b^2+1)/b

QuantityA Quantity B

u(★3) ★(u3)

A.QuantityAis greater.

B.Quantity B is greater.

C.The two quantities are equal.

D.The relationship cannot be determined from the information given.


答案:B

先關注AB的區別,先算括號裡,計算順序不同結果不同

u(★3)=u5=26/5=78/15

★(u3)=★(10/3)=16/3=80/15

u(★3)


3、應用 Applications

3.1、工作問題 work problem

工作量=工作效率ⅹ工作時間

A單獨需要a小時完成, B單獨需要b小時完成, A和B一起需要c小時完成:

1/a+1/b=1/c


例題三:

Working alone, pump A can empty a pool in 3 hours. Working alone, pump B can

empty the same pool in 2 hours. Working together, how many minutes will it take

pumpAand pump B to empty the pool?

A.72

B.75

C.84

D.96

E.108


答案:A

效率:PA=1/3;PB=1/2

A和B一起工作:1/3+1/2=1/t

那所需要的時間為72分鐘


3.2利息問題 interest problem

1、單利

Interest can be computed in two basic ways. With simple annual interest(單利), the interest is computed on the principal only and is equal to (principal)*(interest rate)*time.

F(本金與利息之和)=P(本金)+P×i(利率)×n(計息期數) =P×(1+i×n)


2、複利

If interest is compounded(複利), then interest is computed on the principal as well as on any interest already earned.

F=P*(1+i)^n


例題四:

A certain money market account that had a balance of $48,000 during all of last

month earned $360 in interest for the month.At what simple annual interest rate did

the account earn interest last month?


答案E

月利率:i=360/48000*100%

年利率:I=12i=9%


02

幾何


1、三角形性質:

等邊三角形 equilateral triangle

直角三角形 right triangle


例題一:


一篇讀懂GRE數學中的代數與幾何問題


QuantityA Quantity B

X y

A.QuantityAis greater.

B.Quantity B is greater.

C.The two quantities are equal.

D.The relationship cannot be determined from the information given.


答案B

13+x^2=25

11+y^2=25


2、四邊形性質

平行四邊形 parallelogram

正方形 Square


3、圓 Circles

半徑r、圓周率π、直徑d、R大半徑、h高

圓的面積:πr^2

圓的周長:2πr

半圓的周長:πr+2r

圓環的面積:(R^-r^)π

圓柱的體積:πr^2h

圓柱的表面積:πr^2*2+πdh

圓環的體積:(R^2-r^2)πh


例題二:


一篇讀懂GRE數學中的代數與幾何問題


Quantity A Quantity B

Area of semicircular region Area of triangular region ABC


A.QuantityAis greater.

B.Quantity B is greater.

C.The two quantities are equal.

D.The relationship cannot be determined from the information given.


答案:A

A,B,C都在圓周上,三角形ABC的面積比半圓面積小


4、座標幾何 Coordinate Geometry

1、兩點之間距離

設兩個點A、B以及座標分別為

一篇讀懂GRE數學中的代數與幾何問題

一篇讀懂GRE數學中的代數與幾何問題

,則A和B兩點之間的距離為:


一篇讀懂GRE數學中的代數與幾何問題


2、直線方程

一般式:Ax+By+C=0(A、B不同時為0)【適用於所有直線】

一篇讀懂GRE數學中的代數與幾何問題

一篇讀懂GRE數學中的代數與幾何問題

A1/A2=B1/B2≠C1/C2←→兩直線平行

A1/A2=B1/B2=C1/C2←→兩直線重合

橫截距a=-C/A

縱截距b=-C/B


例題三:

In the xy-coordinate system, the distance between points (2√3,−√2)and(5√3,3√2)

is approximately

A.4.1

B.5.9

C.6.4

D.7.7

E.8.1


答案D

用公式:√[(5√3-2√3)^2+(3√2+√2)^2]=√59≈7.7



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